Question

Фонарь состоит из двух ламп, соединенных параллельно. Сила тока в одной лампе = 40А, в другой – 70 А. Напряжение в цепи 220В. Определите мощность ламп и работу тока во всей цепи за 5 минут

Answer 1

ответ на фото ...............

Answer 2

Calculation of Power and Work in the Circuit

To determine the power and work in the given circuit, we need to use the formulas for power and work in an electrical circuit.

The power (P) in an electrical circuit can be calculated using the formula:

P = I * V

where P is the power, I is the current, and V is the voltage.

The work (W) done by the current in a circuit can be calculated using the formula:

W = P * t

where W is the work, P is the power, and t is the time.

In this case, the circuit consists of two lamps connected in parallel. The current in one lamp is 40A, and the current in the other lamp is 70A. The voltage in the circuit is 220V. We need to calculate the power of each lamp and the work done by the current in the entire circuit in 5 minutes.

Calculation of Power in Each Lamp

To calculate the power in each lamp, we can use the formula:

P = I * V

For the first lamp with a current of 40A:

P1 = 40A * 220V

For the second lamp with a current of 70A:

P2 = 70A * 220V

Calculation of Work in the Entire Circuit

To calculate the work done by the current in the entire circuit, we can use the formula:

W = P * t

where P is the total power in the circuit and t is the time.

To find the total power in the circuit, we can add the powers of the two lamps:

P_total = P1 + P2

Finally, we can calculate the work done by the current in the entire circuit:

W_total = P_total * t

where t is given as 5 minutes.

Let's calculate the values:

P1 = 40A * 220V = 8800WP2 = 70A * 220V = 15400WP_total = P1 + P2 = 8800W + 15400W = 24200W W_total = P_total * t = 24200W * 5 minutes

Please note that the work done by the current in the entire circuit is given in watt-minutes (W-min) or joules (J).