Question

транспортер понимает за 2 часа груз объем ом 300м^3 на высоту 8 м. Определите мощность, если плотность груза 2600кг/м^3​

Answer 1

Ответ: 8,7кВт

Объяснение:

Дано:

t=2ч=7200с

V=300м³

h=8м

ρ=2600кг/м³

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N-?

N=A/t=mgh/t=ρVgh/t=2600*300*10*8/7200=8666,7Вт=8,7кВт

Answer 2

Calculation of Power

To determine the power required by the conveyor, we can use the formula:

Power = Work / Time

The work done by the conveyor can be calculated as the product of the force applied and the distance traveled. In this case, the force can be calculated as the weight of the cargo, and the distance traveled can be calculated as the product of the volume and the height.

Given: - Volume of the cargo (V) = 300 m^3 - Height (h) = 8 m - Density of the cargo (ρ) = 2600 kg/m^3 - Time taken (t) = 2 hours

First, let's calculate the weight of the cargo using the formula:

Weight = Volume x Density x g

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Weight = 300 m^3 x 2600 kg/m^3 x 9.8 m/s^2

Now, let's calculate the distance traveled by the cargo using the formula:

Distance = Volume x Height

Distance = 300 m^3 x 8 m

Finally, we can calculate the power using the formula:

Power = (Weight x Distance) / Time

Let's substitute the values and calculate the power.

Weight = 300 m^3 x 2600 kg/m^3 x 9.8 m/s^2 Distance = 300 m^3 x 8 m Time = 2 hours

Power = (Weight x Distance) / Time

Now, let's calculate the power.

Power = (300 m^3 x 2600 kg/m^3 x 9.8 m/s^2 x 8 m) / (2 hours)

Using the given values, we can calculate the power of the conveyor.