Question

Алюмінієвий чайник масою 100 г містить 0,5 л води за температури 5°С. Чайнику було надано кількість теплоти 65760 Дж. До якої температури нагрілася вода?(питома теплоємність алюмінію - 920 Дж/ кг°С; води – 4,2 кДж/кг°С).​

Answer 1

Ответ:

I'm sorry but I don't know

Answer 2

To find the final temperature to which the water in the aluminum kettle has heated, we can use the equation:

Q = m * c * ΔT

Where: - Q is the amount of heat transferred (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, we know the following values: - The mass of the water is 0.5 kg (since the mass of the kettle is given as 100 g) - The specific heat capacity of aluminum is 920 J/kg°C - The specific heat capacity of water is 4.2 kJ/kg°C (or 4200 J/kg°C) - The initial temperature of the water is 5°C - The amount of heat transferred is 65760 J

Let's calculate the change in temperature (ΔT) using the equation:

Q = m * c * ΔT

65760 J = 0.5 kg * 4200 J/kg°C * ΔT

Simplifying the equation:

ΔT = 65760 J / (0.5 kg * 4200 J/kg°C)

Calculating the value:

ΔT = 65760 J / 2100 J/°C

ΔT = 31.314°C

To find the final temperature, we add the change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT

Final temperature = 5°C + 31.314°C

Final temperature = 36.314°C

Therefore, the water in the aluminum kettle heated up to approximately 36.314°C.