Question

Хоккейная шайба массой 300 г после удара клюшкой, который длился 0,02 с, начала скользить со скоростью 20м/с. Определите среднюю силу удара.​

Answer 1

Ответ:

300 H

Объяснение:

m=0.3 кг    Δt=0.02 c   Δv=20 м/с   F=?

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F=m*a=m*Δv/Δt=0.3*20/0.02=300 H

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Answer 2

Calculation of Average Force

To determine the average force of the hit on the hockey puck, we can use Newton's second law of motion, which states that force (F) is equal to the change in momentum (Δp) divided by the time interval (Δt):

F = Δp / Δt

The change in momentum can be calculated by multiplying the mass of the hockey puck (m) by the change in velocity (Δv):

Δp = m * Δv

Given: - Mass of the hockey puck (m) = 300 g = 0.3 kg - Change in velocity (Δv) = final velocity (v_f) - initial velocity (v_i) = 20 m/s - 0 m/s = 20 m/s

The time interval (Δt) is given as 0.02 s.

Now, let's calculate the average force:

Δp = m * Δv = 0.3 kg * 20 m/s = 6 kg·m/s

F = Δp / Δt = 6 kg·m/s / 0.02 s = 300 N

Therefore, the average force of the hit on the hockey puck is 300 Newtons.