Question

Вертикально вверх брошен мяч с начальной скоростью 4.9м/с.Чему равна его скорость через 0.5с после начала движения?(с противлением воздух пренебреч

Answer 1

По формуле v=v(начальное) - gt v(начальное) = 4,9 t=0.5 g=9.8 (всегда постоянно) Решение: v=4,9-9,8*0,5=0 Ответ:0

Answer 2

Vertical Motion of a Thrown Ball

When a ball is thrown vertically upwards with an initial velocity of 4.9 m/s, we can calculate its velocity at a specific time using the equations of motion. Considering the absence of air resistance, the only force acting on the ball is gravity.

Using the equation for velocity in vertical motion: \[ v = u + at \] where: - \( v \) = final velocity - \( u \) = initial velocity - \( a \) = acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)) - \( t \) = time

Calculating the Velocity

Given: - Initial velocity (\( u \)) = 4.9 m/s - Time (\( t \)) = 0.5 s

Using the equation: \[ v = u + at \] \[ v = 4.9 + (9.81 \times 0.5) \] \[ v = 4.9 + 4.905 \] \[ v = 9.805 \, \text{m/s} \]

The velocity of the ball after 0.5 seconds is approximately 9.805 m/s.