Question

Якщо на менший поршень гідравлічного преса діє сила 110 Н, то на більший поршень площею 1800 см2 передається сила тиску 4,2 кн. Яка площа меншого поршня? ОЧЕНЬ СРОЧНО​

Answer 1

Объяснение:

дано:

F1=110H

S2=1800см²=0,18 м²

F2=4,2кН=4200Н

S1-?

Розв'язання

F1/S1=F2/S2

S1=F1*S2/F2

S1=110Н*0,18м²/4200Н

S1=0,005м²

Answer 2

To find the area of the smaller piston, we can use the formula for pressure:

Pressure = Force / Area

Given that the force on the smaller piston is 110 N and the pressure on the larger piston is 4.2 kN (which is equal to 4200 N), and the area of the larger piston is 1800 cm², we can calculate the area of the smaller piston.

Let's denote the area of the smaller piston as A.

Using the formula for pressure, we can write:

Pressure on the smaller piston = Force on the smaller piston / Area of the smaller piston

Since the pressure is the same throughout the hydraulic system, we can equate the pressures on the smaller and larger pistons:

Pressure on the smaller piston = Pressure on the larger piston

Substituting the values we have:

Force on the smaller piston / Area of the smaller piston = Force on the larger piston / Area of the larger piston

Plugging in the given values:

110 N / A = 4200 N / 1800 cm²

To solve for A, we can cross-multiply and then divide:

110 N * 1800 cm² = 4200 N * A

198000 N cm² = 4200 N * A

198000 N cm² / 4200 N = A

Simplifying:

47 cm² = A

Therefore, the area of the smaller piston is 47 cm².

Please note that the calculations provided are based on the information given in the question.