Question

В тепловом двигателе от нагревателя поступает 1 кДж энергии и выполняется механическая работа 300Дж каков КПД двигателя? С ОБЪЯСНЕНИЕМ ПОЖАЛУЙСТА!!! ДАЮ 40 БАЛЛОВ

Answer 1

Ответ:

410Дж

Объяснение:

Перечитал сам, все должно быть правильно.

Answer 2

Calculation of Efficiency (КПД) of a Heat Engine

To calculate the efficiency (КПД) of a heat engine, we need to know the amount of energy input and the amount of mechanical work output. In this case, we are given that the energy input (нагреватель) is 1 kJ (kilojoule) and the mechanical work output is 300 J (joule).

The efficiency of a heat engine is defined as the ratio of the useful work output to the energy input. Mathematically, it can be expressed as:

Efficiency (КПД) = (Useful work output / Energy input) x 100%

In this case, the useful work output is given as 300 J and the energy input is given as 1 kJ. We can convert 1 kJ to joules by multiplying it by 1000:

1 kJ = 1000 J

Now we can substitute the values into the efficiency formula:

Efficiency (КПД) = (300 J / 1000 J) x 100%

Simplifying the expression:

Efficiency (КПД) = 0.3 x 100%

Calculating the efficiency:

Efficiency (КПД) = 30%

Therefore, the efficiency of the heat engine is 30%.

Please note that the search results did not provide any relevant information for this specific calculation. However, the calculation of efficiency for a heat engine is a well-known concept in thermodynamics and can be derived using the principles of energy conservation and the first law of thermodynamics.