Question

На ящик массой 72 кг с его содержимым помещен груз массой 12 кг.Если площадь одной ножки ящика 4 см на 15 см, найти полное давление ящика? Обозначьте дерево кПа . пожалуйста помогите ​

Answer 1

Какие из перечисленных ниже явлений можно отнести к механическим, электрическим, магнитным, тепловым, звуковым, световым: а) со стола падает чашка и разбивается; б) машина скорой помощи подает сигнал; в) весной на улице тает снег; г) потертая о шерстян

2. Приведите примеры тел, имеющих разный объем, но одинаковую форму и, наоборот, разную форму и одинаковый объем.

3. Из каких веществ состоят следующие предметы (физические тела): ластик, капля росы, чашка, бутылка (рис.1)?

4. Запишите несколько физических тел, состоящих из одного и того же вещества.

Объяснение:

Вот бро удачи

Answer 2

Calculation of Pressure

To find the total pressure exerted by the box, we need to calculate the pressure exerted by the box itself and the pressure exerted by the additional load.

The pressure exerted by an object can be calculated using the formula:

Pressure = Force / Area

In this case, the force is the weight of the object, and the area is the area of one leg of the box.

Let's calculate the pressure step by step:

1. Calculate the pressure exerted by the box: - Mass of the box = 72 kg - Weight of the box = mass * acceleration due to gravity - Acceleration due to gravity is approximately 9.8 m/s^2 - Weight of the box = 72 kg * 9.8 m/s^2 - Force exerted by the box = weight of the box - Area of one leg of the box = 4 cm * 15 cm (converted to meters) - Pressure exerted by the box = Force exerted by the box / Area of one leg of the box

2. Calculate the pressure exerted by the additional load: - Mass of the additional load = 12 kg - Weight of the additional load = mass * acceleration due to gravity - Weight of the additional load = 12 kg * 9.8 m/s^2 - Force exerted by the additional load = weight of the additional load - Area of one leg of the box = 4 cm * 15 cm (converted to meters) - Pressure exerted by the additional load = Force exerted by the additional load / Area of one leg of the box

3. Calculate the total pressure: - Total pressure = Pressure exerted by the box + Pressure exerted by the additional load

Let's calculate the values:

1. Pressure exerted by the box: - Weight of the box = 72 kg * 9.8 m/s^2 = 705.6 N - Area of one leg of the box = 4 cm * 15 cm = 0.04 m * 0.15 m = 0.006 m^2 - Pressure exerted by the box = 705.6 N / 0.006 m^2 = 117,600 Pa

2. Pressure exerted by the additional load: - Weight of the additional load = 12 kg * 9.8 m/s^2 = 117.6 N - Area of one leg of the box = 4 cm * 15 cm = 0.04 m * 0.15 m = 0.006 m^2 - Pressure exerted by the additional load = 117.6 N / 0.006 m^2 = 19,600 Pa

3. Total pressure: - Total pressure = 117,600 Pa + 19,600 Pa = 137,200 Pa

Therefore, the total pressure exerted by the box and its contents is 137,200 Pa.

Please note that the values provided are based on the given information and calculations.