Question

7. У магнітне поле з індукцією 0,5 мТл перпендикулярно до ліній магнітної індукції влітає електрон зі швидкістю 109 м/с. Знайдіть радіус кола, по якому рухається частинка. Маса та заряд електрона дорівнюють 9,1-10-31 кг і -1,6-10-19 К відповідно.​ Срочнооооо

Answer 1

Ответ:

11,375 м

Объяснение:

В=0,5 мТл;

α=90°;

V=10⁹ м/с

m=9,1-10⁻³¹ кг

e=-1,6-10⁻¹⁹ Кл

R  ?  R=mV/(e*B)=9,1-10⁻³¹*10⁹/(|-1,6-10⁻¹⁹|*0,5*10⁻³)=11,375 м

Answer 2

To find the radius of the circle along which the electron moves in a magnetic field, we can use the formula for the centripetal force acting on a charged particle in a magnetic field. The centripetal force is provided by the magnetic force acting on the electron.

The formula for the magnetic force on a charged particle moving in a magnetic field is given by:

F = qvB

Where: - F is the magnetic force - q is the charge of the particle - v is the velocity of the particle - B is the magnetic field strength

In this case, the charge of the electron is -1.6 x 10^-19 C, the velocity is 1.09 x 10^9 m/s, and the magnetic field strength is 0.5 mT (which is equivalent to 0.5 x 10^-3 T).

Substituting the given values into the formula, we have:

F = (-1.6 x 10^-19 C) x (1.09 x 10^9 m/s) x (0.5 x 10^-3 T)

Now, we know that the magnetic force provides the centripetal force for the circular motion of the electron. The centripetal force is given by:

F = (mv^2) / r

Where: - m is the mass of the particle - v is the velocity of the particle - r is the radius of the circular path

In this case, the mass of the electron is 9.1 x 10^-31 kg.

Equating the magnetic force and the centripetal force, we have:

(mv^2) / r = (-1.6 x 10^-19 C) x (1.09 x 10^9 m/s) x (0.5 x 10^-3 T)

Now, we can solve for the radius of the circular path (r):

r = (mv^2) / (qB)

Substituting the given values into the formula, we have:

r = (9.1 x 10^-31 kg) x (1.09 x 10^9 m/s)^2 / (-1.6 x 10^-19 C) x (0.5 x 10^-3 T)

Calculating the value, we find:

r ≈ 0.001 m

Therefore, the radius of the circle along which the electron moves is approximately 0.001 meters.

Please note that the above calculation is based on the given values and assumptions.