Question

3. Два резистора, сопротивлением 40 и 60 Ом, включены в электрическую цепь напряжением 72 В. Какова сила тока в этой цепи при последовательном и параллельном соединении резисторов? [4]​

Answer 1

Ответ:

0,72 А     3 А

Объяснение:

R1=40 Ом   R2=60 Ом    U=72 B    I1=?   I2=?

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Последовательно

I1=U/(R1+R2)=72/(40+60)=0.72 A

Параллельно

I2=U*(R1+R2)/(R1*R2)=72*(40+60)/(40*60)=3 A

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Answer 2

Calculation of Current in Series and Parallel Circuit

To calculate the current in a circuit with resistors connected in series or parallel, we need to apply Ohm's Law and the rules for series and parallel resistances.

1. Series Connection: In a series connection, the resistors are connected end-to-end, so the current passing through each resistor is the same. The total resistance in a series circuit is the sum of the individual resistances.

To calculate the current in a series circuit, we can use Ohm's Law: I = V/R, where I is the current, V is the voltage, and R is the total resistance.

In this case, we have two resistors with resistances of 40 Ω and 60 Ω, and a voltage of 72 V. The total resistance in a series circuit is the sum of the individual resistances: R_total = R1 + R2.

Let's calculate the current in the series circuit:

- R1 = 40