Question

Даю 50 балов!! помогите! Під дією сили 640 Н пружина амортизатора стиснулася на 4 мм. На скільки вона стиснеться під дією сили 1,6 кН? Відповідь подайте в міліметрах

Answer 1

Ответ:

10мм

Объяснение:

640Н - 0.64кН. 1,6кН - 1600 Н 1600:640= 2,5 . 4 мм • 2,5 = 10 ми

Answer 2

Calculation of Spring Compression

To calculate the compression of the spring under the force of 1.6 kN, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force applied to the spring (1.6 kN = 1600 N) - k is the spring constant (unknown) - x is the displacement of the spring (unknown)

We can rearrange the equation to solve for x:

x = F / k

To find the spring constant, we can use the given information that the spring was compressed by 4 mm (0.004 m) under a force of 640 N.

640 N = k * 0.004 m

Solving for k:

k = 640 N / 0.004 m

Now we can substitute the values of F and k into the equation to find x:

x = (1600 N) / (640 N / 0.004 m)

Calculating the value of x:

x = (1600 N) / (640 N / 0.004 m) = 0.01 m = 10 mm

Therefore, the spring will compress by 10 mm under the force of 1.6 kN.

Please note that the calculation assumes that the spring follows Hooke's Law and behaves linearly within the given range of displacement and force.