Question

Конденсатор электроёмкостью 0,05 мкФ соединили с источником тока, вследствие чего он получил заряд 50 нКл. Определите напряженность поля между пластинами конденсатора, если расстояние между ними 0,5мм. (Решите задачу,полночью оформив,спасибо).

Answer 1

E=U/d
U=Cq
E=Cq/d= 0.05*10^-6*50*10^-9 / 0.5*10^-3= 5*10^-9 или 5 (нКл)

Answer 2

Calculation of Electric Field Intensity

To determine the electric field intensity between the plates of a capacitor, we can use the formula:

E = Q / (ε₀ * A)

Where: - E is the electric field intensity - Q is the charge on the capacitor plates - ε₀ is the permittivity of free space (8.85 x 10^-12 F/m) - A is the area of the capacitor plates

In this case, the charge on the capacitor plates is given as 50 nC (nanocoulombs) and the distance between the plates is 0.5 mm (millimeters).

To find the area of the capacitor plates, we need to know the dimensions of the plates. Unfortunately, the given information does not provide the necessary details to calculate the area.

Please provide the dimensions of the capacitor plates (length and width) so that we can proceed with the calculation.