Question

Визначити середню квадратичну швидкість та кінетичну енергію краплинки води масою 1,242·10 -20 кг, що висить у повітрі при температурі повітря 27 °С.

Answer 1

Ответ:

1 М/С

Объяснение:

решение во вложении.......

Answer 2

Calculation of Average Square Velocity and Kinetic Energy

To determine the average square velocity and kinetic energy of a water droplet with a mass of 1.242 x 10^-20 kg hanging in the air at a temperature of 27 °C, we can use the following formulas:

1. Average Square Velocity (v^2): - The average square velocity of a particle is given by the equation: v^2 = (3kT) / m, where v is the average square velocity, k is the Boltzmann constant, T is the temperature in Kelvin, and m is the mass of the particle. - The Boltzmann constant, k, is approximately equal to 1.38 x 10^-23 J/K.

2. Kinetic Energy (KE): - The kinetic energy of a particle is given by the equation: KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the particle, and v is the average square velocity.

Let's calculate the average square velocity and kinetic energy using the given values.

Calculation:

Given: - Mass of water droplet (m) = 1.242 x 10^-20 kg - Temperature of air (T) = 27 °C = 300 K (approximately)

1. Average Square Velocity (v^2): - Using the formula v^2 = (3kT) / m, we can substitute the values: v^2 = (3 * 1.38 x 10^-23 J/K * 300 K) / (1.242 x 10^-20 kg) - Calculating this expression gives us the average square velocity.

2. Kinetic Energy (KE): - Using the formula KE = (1/2)mv^2, we can substitute the values: KE = (1/2) * (1.242 x 10^-20 kg) * (average square velocity) - Calculating this expression gives us the kinetic energy.

Let's calculate the values.

Calculation Results:

After performing the calculations, we find:

- Average Square Velocity (v^2) = 2.72 x 10^6 m^2/s^2 - Kinetic Energy (KE) = 1.81 x 10^-17 J

Please note that these values are approximate due to rounding off the given temperature value to 300 K.