Question

Четыре резистора соединены параллельно, их сопротивления равны 2 Ом, 4 Ом, 6 Ом и 8 Ом. Какова сила тока в каждом резисторе, если в общей части цепи течет ток силой 50 А? Каково напряжение на каждом резисторе?

Answer 1

Ответ:

1/Rобщ = 1/2 + 1/4 + 1/6 + 1/8

1/Rобщ = 25/24

Rобщ = 24/25

Uобщ = Iобщ * Rобщ = 50А * 24/25 = 48В

Uобщ = U1 = U2 = U3 = U4

I1 = 48/2 = 24А

I2 = 48/4 = 12А

I3 = 48/6 = 8А

I4 = 48/8 = 6А

Answer 2

Calculation of Current in Each Resistor:

To find the current flowing through each resistor, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R). In this case, the voltage across each resistor is the same because they are connected in parallel.

Let's calculate the current flowing through each resistor:

- Resistor 1: Resistance = 2 Ω - Resistor 2: Resistance = 4 Ω - Resistor 3: Resistance = 6 Ω - Resistor 4: Resistance = 8 Ω

The total current flowing through the circuit is given as 50 A.

Using Ohm's Law, we can calculate the current in each resistor:

- Resistor 1: I1 = V/R = 50 A / 2 Ω = 25 A - Resistor 2: I2 = V/R = 50 A / 4 Ω = 12.5 A - Resistor 3: **I3 =