Question

Хлопчик тягне санчата, прикладаючи силу 50 Н, напрямлену під кутом 60° до горизонту. Яку потужність розвиває хлопчик, якщо санчата рухаються рівномірно прямолінійно і за хвилину перемістилися на 30 м?​

Answer 1

Дано:

F = 50 H

∠$\alpha$ = 60°

l = 30 м

t = 60 с

Знайти N = ?Вт

Розв'язання:

N = A / t

A = F * l * cos $\alpha$

N = $\frac{F * l * cos \alpha }{t} = \frac{50 * 30*\frac{1}{2}}{60} = 12,5$ Ватт

Відповідь: 12,5 Ватт.

Answer 2

To calculate the power developed by the boy, we need to use the formula:

Power = Work / Time

First, let's calculate the work done by the boy. The work done is given by the formula:

Work = Force * Distance * cos(theta)

where: - Force = 50 N (the force applied by the boy) - Distance = 30 m (the distance the sleds moved) - theta = 60° (the angle between the force and the horizontal direction)

Plugging in the values, we get:

Work = 50 N * 30 m * cos(60°)

To find the value of cos(60°), we can use the trigonometric identity:

cos(60°) = 0.5

Substituting this value into the equation, we have:

Work = 50 N * 30 m * 0.5

Now, let's calculate the time taken to move the sleds. We are given that the sleds moved a distance of 30 m in 1 minute (60 seconds). Therefore, the time taken is:

Time = 60 seconds

Finally, we can calculate the power developed by the boy using the formula:

Power = Work / Time

Substituting the values, we get:

Power = (50 N * 30 m * 0.5) / 60 seconds

Simplifying the equation, we have:

Power = 25 N * 0.5 m / 60 seconds

Power = 0.4167 Nm/s

Therefore, the power developed by the boy is approximately 0.4167 Nm/s.