Question

За какое время на сопротивлении выделится 880 Дж тепла, если падение напряжения на нем 220 В, и сила тока 0.5 А?

Answer 1

Q=UIt⇒t=Q/(IU)

 t=880/(220*0.5)=8c

Answer 2

Calculating the Time for Heat Dissipation

To calculate the time it takes for a resistor to dissipate 880 J of heat when a voltage drop of 220 V and a current of 0.5 A are applied, we can use the formula:

Time (t) = Energy (Q) / Power (P)

Where: - Energy (Q) = 880 J - Power (P) = Voltage (V) * Current (I)

Let's calculate the power first using the given voltage and current.

Calculating Power (P)

Using the formula for power:

Power (P) = Voltage (V) * Current (I)

Substitute the given values: - Voltage (V) = 220 V - Current (I) = 0.5 A

Power (P) = 220 V * 0.5 A

Power (P) = 110 W

Calculating Time (t)

Now, we can calculate the time using the formula:

Time (t) = Energy (Q) / Power (P)

Substitute the given values: - Energy (Q) = 880 J - Power (P) = 110 W

Time (t) = 880 J / 110 W

Time (t) = 8 seconds

So, it will take 8 seconds for the resistor to dissipate 880 J of heat.