
Задача 2. Вагон рухається рівноприскорено із прискоренням -0,5 м/с2. Початкова швидкість вагона
дорівнює 54 км/год. За скільки часу вагон зупиниться? Побудуйте графік залежності швидкості часу.

Ответы на вопрос

To solve this problem, we can use the equations of motion. The equation that relates acceleration, initial velocity, final velocity, and time is:
v = u + at
where: - v is the final velocity - u is the initial velocity - a is the acceleration - t is the time
In this case, the acceleration is -0.5 m/s^2 (negative because it is deceleration), and the initial velocity is 54 km/h. We need to convert the initial velocity to m/s before using it in the equation.
To convert 54 km/h to m/s, we can use the conversion factor: 1 km/h = 0.2778 m/s. Therefore, the initial velocity is:
u = 54 km/h * 0.2778 m/s = 15 m/s
Now, let's solve for the time it takes for the wagon to stop. We know that the final velocity is 0 m/s (since the wagon stops), and the acceleration is -0.5 m/s^2. Substituting these values into the equation, we have:
0 = 15 m/s + (-0.5 m/s^2) * t
Simplifying the equation, we get:
0.5t = 15
Dividing both sides by 0.5, we find:
t = 30 seconds
Therefore, the wagon will stop in 30 seconds.
Now, let's plot the graph of velocity versus time. The initial velocity is 15 m/s, and the acceleration is -0.5 m/s^2. The graph will be a straight line with a negative slope, starting at 15 m/s and decreasing until it reaches 0 m/s at 30 seconds.
Graph of Velocity vs. Time:
``` import matplotlib.pyplot as plt# Time values from 0 to 30 seconds time = range(31)
# Calculate velocity at each time point velocity = [15 - 0.5 * t for t in time]
# Plot the graph plt.plot(time, velocity) plt.xlabel('Time (s)') plt.ylabel('Velocity (m/s)') plt.title('Velocity vs. Time') plt.grid(True) plt.show() ```
The graph will show a linear decrease in velocity over time, starting at 15 m/s and reaching 0 m/s at 30 seconds.
Please note that the code provided is a basic example and may require additional libraries or modifications to run properly in your specific environment.


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