Question

Физика, 8 класс. Одна калория - энергия, которую необходимо передать одному грамму воды, чтобы нагреть её на один градус Цельсия. Калорийность шоколадного батончика 330 кКал. Сколько льда (в кг), взято при температуре плавления, можно превратить воду, если использовать всю эту энергию, запасённую в батончика? Удельная теплоемкость воды c=4200Дж/кг*⁰C, удельная теплота плавления льда лянда=3,3*10⁵ Дж/кг.

Answer 1

Ответ:

4,2 кг

Объяснение:

330 кКал = 1386000 Дж

m = Q / λ

m = 1386000 Дж / 330000 Дж / кг = 4,2 кг

Answer 2

Calculation of the Amount of Ice that can be Converted to Water

To calculate the amount of ice that can be converted to water using the energy stored in the chocolate bar, we need to consider the specific heat capacity of water and the latent heat of fusion of ice.

Given: - Calorific value of the chocolate bar = 330 kCal - Specific heat capacity of water (c) = 4200 J/kg°C - Latent heat of fusion of ice (λ) = 3.3 x 10^5 J/kg

To find the amount of ice that can be converted to water, we can use the following formula:

Energy = Mass x Specific Heat Capacity x Change in Temperature + Mass x Latent Heat of Fusion

Let's assume the mass of ice to be converted is 'm' kg.

The energy stored in the chocolate bar is given by:

Energy = 330 kCal = 330 x 10^3 x 4.18 x 10^3 J

The change in temperature is the difference between the melting point of ice (0°C) and the initial temperature of the ice, which is the temperature at which it is taken.

Substituting the values into the formula, we get:

330 x 10^3 x 4.18 x 10^3 J = m x 4200 J/kg°C x (0 - T)

Simplifying the equation, we find:

m = (330 x 10^3 x 4.18 x 10^3 J) / (4200 J/kg°C x T)

where 'T' is the initial temperature of the ice in °C.

Please provide the initial temperature of the ice so that we can calculate the mass of ice that can be converted to water using the energy stored in the chocolate bar.