Question

Пуля вылетает, держа курс с запада на восток, в штиль, имея скорость 15,5 м/с. Попутно дует лёгкий весенний ветерок, имея скорость 3 м/с. Запиши модуль скорости, с которой станет теперь лететь пуля относительно автомобиля, стоящего на парковке. Ответ (запиши с точностью до десятых): м/с.

Answer 1

Ответ: 18.5м/с

Объяснение: Машина неподвижна относительно земли, значит можем найти скорость пули относительно земли.

Answer 2

Calculation of Bullet's Speed Relative to the Parked Car

To calculate the speed of the bullet relative to the parked car, we need to consider the vector addition of the bullet's velocity and the wind velocity.

Given: - Bullet's velocity: 15.5 m/s towards the east (from west to east) - Wind velocity: 3 m/s towards the east (from west to east)

To find the resultant velocity, we can add the velocities vectorially. Since both velocities are in the same direction (east), we can simply add their magnitudes.

The magnitude of the resultant velocity can be calculated using the Pythagorean theorem:

Resultant velocity = sqrt((bullet velocity)^2 + (wind velocity)^2)

Let's calculate the resultant velocity:

Resultant velocity = sqrt((15.5 m/s)^2 + (3 m/s)^2)

Calculating the above expression, we find:

Resultant velocity = sqrt(240.25 m^2/s^2 + 9 m^2/s^2) ≈ 15.6 m/s

Therefore, the module of the speed with which the bullet will now fly relative to the parked car is approximately 15.6 m/s.