Question

Тело весом 10 кг, первоначально движущееся со скоростью 10 метров в секунду, совершает лобовое столкновение с телом весом 15 кг, первоначально находящимся в состоянии покоя. Два объекта слипаются. Какова скорость (в м/с) получившегося тела сразу после столкновения?

Answer 1

Ответ:

13,3м м/с

Объяснение:

10*15+5*10/10+5=13,3 м/с

Answer 2

Calculation of the velocity of the combined object after collision

To calculate the velocity of the combined object after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

Where: - p is the momentum of the object, - m is the mass of the object, and - v is the velocity of the object.

In this case, we have two objects colliding and sticking together. Let's denote the velocity of the 10 kg object as v1 and the velocity of the 15 kg object as v2. After the collision, the two objects combine to form a single object with a mass of 10 kg + 15 kg = 25 kg.

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:

m1 * v1 + m2 * v2 = (m1 + m2) * v

Where: - m1 is the mass of the 10 kg object, - v1 is the velocity of the 10 kg object, - m2 is the mass of the 15 kg object, - v2 is the velocity of the 15 kg object, and - v is the velocity of the combined object after the collision.

Since the 15 kg object is initially at rest (v2 = 0), the equation simplifies to:

10 kg * 10 m/s + 15 kg * 0 = 25 kg * v

Simplifying further, we have:

100 kg·m/s = 25 kg * v

Dividing both sides of the equation by 25 kg, we get:

4 m/s = v

Therefore, the velocity of the combined object immediately after the collision is 4 m/s.