Question

Лыжник из состояния покоя спускается с горы с постоянным ускорением ,равным 0,8 м/с^2.Какую скорость будет иметь велосипедист через 10 с,если его начальная скорость была 2,0 м/с.

Answer 1

a-0.8м/c

t-10с

V(нулевое)-2м/c

Найти:V-?

Решение:V=ax умножит на t+V(нулевая)=0.8 умноженное на 10+2=10

Answer 2

Problem Analysis

The problem describes a skier descending a mountain from a state of rest with a constant acceleration of 0.8 m/s^2. We are asked to find the velocity of a cyclist after 10 seconds, given that their initial velocity is 2.0 m/s.

Solution

To solve this problem, we can use the equations of motion to find the final velocity of the cyclist after 10 seconds.

The equation of motion for an object with constant acceleration is given by: v = u + at

Where: - v = final velocity - u = initial velocity - a = acceleration - t = time

Using this equation, we can calculate the final velocity of the cyclist.

Calculation

Given: - Initial velocity of the cyclist, u = 2.0 m/s - Time, t = 10 s - Acceleration, a = 0.8 m/s^2

Using the equation v = u + at, we can calculate the final velocity of the cyclist: v = 2.0 m/s + (0.8 m/s^2 * 10 s)

Result

Calculating the final velocity: v = 2.0 m/s + (0.8 m/s^2 * 10 s) v = 2.0 m/s + 8 m/s v = 10 m/s

Answer

The velocity of the cyclist after 10 seconds will be 10 m/s.