Question

при подходе к станции поезд, имея начальную скорость 90 км/ч, остановился через 50с. Определите модуль ускорения поезда при торможении.

Answer 1

Дано:                                            Решение:

t=50сек                                         а=V-Vo/t=0-25/50=-25/50=-1/2=-0,5М/с^2(^-степ)

Vо=90км/ч=25м/с

V=0м/с(т.к. поезд остановился)    

а-?

Answer 2

Calculation of the Train's Deceleration

To determine the magnitude of the train's deceleration, we can use the formula:

acceleration = (final velocity - initial velocity) / time

Given that the initial velocity of the train is 90 km/h and it comes to a stop in 50 seconds, we can calculate the deceleration.

Let's convert the initial velocity from km/h to m/s:

initial velocity = 90 km/h = (90 * 1000) / 3600 m/s = 25 m/s.

The final velocity is 0 m/s since the train comes to a stop.

Plugging in the values into the formula:

acceleration = (0 - 25) / 50 = -0.5 m/s^2

Therefore, the magnitude of the train's deceleration is 0.5 m/s^2.

Please note that the negative sign indicates that the train is decelerating or slowing down.