Question

3. На плавком предохранителе, вставленном в телевизор мощностью 400 Вт, рассчитанный на напряжение 220 В, написано «2 A». Временаминапряжение в сети превышает 220 В. При каком значении напряжения всети предохранитель расплавится?​

Answer 1

Ответ:

220B×1,1=242B ответ правильно

Объяснение:

ток меньше предельного в1.1раза ток пропорционален напражению если напряжение увеличить в 1.1 раза то и ток увеличится в 1.1 и станет равным 2А предохранитель перегорит.

Answer 2

Understanding the Question

The question is asking about the voltage at which a fuse in a television, rated for 220V and 2A, will melt if the voltage in the power supply exceeds 220V. We need to determine the voltage at which the fuse will melt.

Answer

To determine the voltage at which the fuse will melt, we need to consider the power rating of the television and the current rating of the fuse.

The power rating of the television is given as 400W, and the voltage rating is 220V. We can use the formula P = VI, where P is power, V is voltage, and I is current, to find the current drawn by the television.

Given that the power is 400W and the voltage is 220V, we can rearrange the formula to solve for current:

I = P / V

Substituting the values, we get:

I = 400W / 220V = 1.82A

So, the television draws a current of approximately 1.82A.

Now, let's consider the fuse. The fuse is rated for 2A, which means it can handle a maximum current of 2A without melting. If the current exceeds 2A, the fuse will melt and break the circuit, protecting the television from damage.

Since the fuse is rated for 2A, we know that it will not melt as long as the current remains below 2A. However, if the current exceeds 2A, the fuse will melt and break the circuit.

To find the voltage at which the fuse will melt, we need to determine the current when the voltage exceeds 220V. We can use the formula I = P / V, where I is the current, P is the power, and V is the voltage.

Let's assume the voltage in the power supply exceeds 220V by a certain amount, which we'll call ΔV. The new voltage would be 220V + ΔV.

Using the formula I = P / V, we can calculate the new current:

I = 400W / (220V + ΔV)

Now, we need to find the value of ΔV when the current exceeds 2A (the maximum current rating of the fuse).

Let's solve the equation:

2A = 400W / (220V + ΔV)

To find ΔV, we can rearrange the equation:

ΔV = (400W / 2A) - 220V

Simplifying the equation:

ΔV = 200V - 220V = -20V

From the equation, we can see that the voltage at which the fuse will melt is 220V - 20V = 200V.

Therefore, if the voltage in the power supply exceeds 200V, the fuse in the television will melt and break the circuit.

Note: It's important to note that this calculation assumes ideal conditions and does not take into account other factors that may affect the behavior of the fuse. It's always recommended to consult the manufacturer's specifications and guidelines for accurate information about the fuse's behavior.