Question

Когда стальная пружина растягивается на 1 см, потенциальная энергия упругого удлинения составляет 1 Дж. Какова потенциальная энергия этой пружины при растяжении на 2 см? 5 Дж. 0,2 Дж. 6 Дж. 3 Дж. 4 Дж.​

Answer 1

Ответ:

4 Дж

Объяснение:

x1=1 см    W1=1 Дж    x2=2 см    W2=?

===

W1=k*x1²/2

W2=k*x2²/2

W2=W1*(x2/x1)²=1*(2/1)²=4 Дж

=========================

Answer 2

Calculation of Potential Energy for a Stretched Spring

To calculate the potential energy of a spring when stretched, we can use the formula:

Potential Energy = (1/2) * k * x^2

Where: - k is the spring constant, which represents the stiffness of the spring. - x is the displacement or elongation of the spring from its equilibrium position.

In this case, we are given that the potential energy of the spring when stretched by 1 cm is 1 J. We need to find the potential energy when the spring is stretched by 2 cm.

Let's calculate it step by step:

1. We know that the potential energy of the spring when stretched by 1 cm is 1 J. Using this information, we can set up the equation:

1 J = (1/2) * k * (1 cm)^2

2. Now, we need to find the value of the spring constant k. To do this, we can rearrange the equation:

k = (2 * 1 J) / (1 cm)^2

Simplifying the equation, we get:

k = 2 J/cm^2

3. Finally, we can calculate the potential energy of the spring when stretched by 2 cm using the formula:

Potential Energy = (1/2) * k * (2 cm)^2

Substituting the value of k we found earlier, we get:

Potential Energy = (1/2) * (2 J/cm^2) * (2 cm)^2

Simplifying the equation, we get:

Potential Energy = 4 J

Therefore, the potential energy of the spring when stretched by 2 cm is 4 J.