Question

Какова масса груза, подвешенного к пружине жесткостью 200 Н/м, если под действием веса груза она растянулась на 10 см? (ответ запишите в кг)​

Answer 1

Ответ:

2 кг

Объяснение:

k=200 Н/м    x=0.1 м    m=?

===

F=k*x=m*g

m=k*x/g=200*0.1/10=2 кг

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Answer 2

Calculation of the Mass of the Suspended Load

To calculate the mass of the load suspended from a spring with a stiffness of 200 N/m, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

The formula for Hooke's Law is:

F = kx

Where: - F is the force exerted by the spring, - k is the stiffness of the spring, and - x is the displacement of the spring from its equilibrium position.

In this case, the spring is stretched by 10 cm (or 0.1 m) under the weight of the load. We can substitute the given values into the formula to find the force exerted by the spring:

F = 200 N/m * 0.1 m

Simplifying the equation:

F = 20 N

Now, to find the mass of the load, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force acting on the load is the force exerted by the spring, which we found to be 20 N.

Since the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the mass of the load using the formula:

F = m * g

Where: - F is the force acting on the load (20 N), - m is the mass of the load (to be determined), and - g is the acceleration due to gravity (9.8 m/s^2).

Rearranging the equation to solve for mass:

m = F / g

Substituting the values:

m = 20 N / 9.8 m/s^2

Calculating the mass:

m ≈ 2.04 kg

Therefore, the mass of the load suspended from the spring with a stiffness of 200 N/m is approximately 2.04 kg.