Question

Максимальная высота, на которую поднимается тело массой 1 кг, подброшенное вертикально вверх, составляет 20 м. Найдите чему была равна кинетическая энергия тела сразу же после броска. рисунок к задаче​

Answer 1

Ответ:

m = 1 кг

h = 20 м

g = 10 м/с^2

Е = mgh = 1 * 10 * 20 = 200 (Дж)

Answer 2

Calculation of Kinetic Energy

To find the kinetic energy of the object immediately after being thrown vertically upwards, we can use the formula for kinetic energy:

Kinetic Energy (KE) = (1/2) * mass * velocity^2

Given: - Mass of the object (m) = 1 kg - Maximum height reached (h) = 20 m

To calculate the velocity of the object at the maximum height, we can use the principle of conservation of mechanical energy. At the maximum height, the object's kinetic energy is zero, and all its initial kinetic energy is converted into potential energy.

Potential Energy (PE) = mass * gravity * height

At the maximum height, the potential energy is equal to the initial kinetic energy:

PE = KE

Substituting the values:

mass * gravity * height = (1/2) * mass * velocity^2

Simplifying:

velocity^2 = 2 * gravity * height

Taking the square root of both sides:

velocity = sqrt(2 * gravity * height)

Now we can calculate the kinetic energy using the formula mentioned earlier:

KE = (1/2) * mass * velocity^2

Substituting the values:

KE = (1/2) * 1 kg * (sqrt(2 * gravity * height))^2

Simplifying:

KE = (1/2) * 1 kg * 2 * gravity * height

KE = gravity * height

Therefore, the kinetic energy of the object immediately after being thrown vertically upwards is equal to the product of the acceleration due to gravity and the height reached.

Let's calculate the value using the standard acceleration due to gravity of 9.8 m/s^2:

KE = 9.8 m/s^2 * 20 m

KE = 196 Joules

So, the kinetic energy of the object immediately after being thrown vertically upwards is 196 Joules.

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