Question

Яка кількість теплоти виділилась при охолодженні олії, об'єм якої 10 л, якщо температура змінилася від 60 до 20 градусів

Answer 1

Ответ:

Объяснение:

V = 10 л = 0.001 м^3

t1 =  60 °C

t2 =  20 °C

p = 900 кг/м^3 плотность масла

c = 1700 Дж/кг*К   удельная теплоемкость масла

Q = ?

m = V*p

Q = m*c*(t2 - t1) = V*p*c*(t2-t1) = 0.001*900*1700*(20-60) = - 61.2  килоДжоуля

Answer 2

Calculation of Heat Released during Cooling of Oil

To calculate the amount of heat released during the cooling of oil, we need to use the formula:

Q = mcΔT

Where: - Q is the amount of heat released or absorbed (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, we are given the following information: - The volume of oil is 10 liters. - The temperature change is from 60 degrees Celsius to 20 degrees Celsius.

To calculate the mass of the oil, we need to know its density. Unfortunately, the given information does not include the density of the oil. Therefore, we cannot accurately calculate the amount of heat released during the cooling process.

If you have any additional information, such as the density or specific heat capacity of the oil, please provide it, and I will be happy to help you with the calculation.