Question

Пуля в стволе автомата Калашникова движится с ускорением 616 км/с². какова скорость вылета пули, если длина ствола 41,5 см?

Answer 1

Переведем сначала ускорение из км/с^2 в м/с* получится 616000м/с*
41.5 см переведем в метры, это будет 0.415м. а скорость будет равна корню из (0.415*616000) = корень из 255640

Answer 2

Calculation of Bullet Exit Velocity

To calculate the exit velocity of a bullet fired from an AK-47 rifle, we can use the formula for acceleration:

acceleration = change in velocity / time

In this case, the acceleration is given as 616 km/s² and the length of the barrel is 41.5 cm. We need to convert the acceleration to m/s² and the length of the barrel to meters.

Converting the acceleration: 616 km/s² = 616,000 m/s²

Converting the length of the barrel: 41.5 cm = 0.415 m

Now, we can rearrange the formula to solve for the change in velocity:

change in velocity = acceleration * time

Since we are given the acceleration and the length of the barrel, we need to find the time it takes for the bullet to travel through the barrel. Unfortunately, the time is not provided in the question, so we cannot calculate the exit velocity without this information.

Please provide the time it takes for the bullet to travel through the barrel, and I will be happy to help you calculate the exit velocity.