Question

Летчик выводит самолет из пикирования. Скорость самолёта 300 м/с. Радиус траектории 1 км. Масса летчика 70 кг. Определите вес летчика в нижней точке траектории.

Answer 1

P=m*(g+a)=m*(g+V^2/R)=70*(10+300^2/1000)=7000 H

Answer 2

Calculating the Weight of the Pilot at the Bottom of the Trajectory

To calculate the weight of the pilot at the bottom of the trajectory, we can use the principles of circular motion and centripetal force. The centripetal force required to keep the pilot and the aircraft in circular motion can be equated to the gravitational force acting on the pilot.

Given: - Speed of the aircraft (v) = 300 m/s - Radius of the trajectory (r) = 1 km = 1000 m - Mass of the pilot (m) = 70 kg - Acceleration due to gravity (g) = 9.81 m/s^2

The centripetal force (Fc) required to keep the pilot and the aircraft in circular motion can be calculated using the formula: Fc = m * v^2 / r

Where: - Fc = Centripetal force - m = Mass of the pilot - v = Speed of the aircraft - r = Radius of the trajectory

The weight of the pilot at the bottom of the trajectory can be calculated using the formula: Weight = mass * acceleration due to gravity

Let's calculate the weight of the pilot at the bottom of the trajectory using the given values.

Calculations

First, we calculate the centripetal force: Fc = m * v^2 / r Fc = 70 kg * (300 m/s)^2 / 1000 m Fc = 6300000 N

Next, we calculate the weight of the pilot: Weight = mass * acceleration due to gravity Weight = 70 kg * 9.81 m/s^2 Weight ≈ 686.7 N

Conclusion

The weight of the pilot at the bottom of the trajectory is approximately 686.7 Newtons.