Question

Автомобиль кота Леопольда , на котором убегали мыши ,остановился под действием силы трения, равной 40 Н, пройдя по горизонтальному участку дороги путь 25 м. Определите работу силы трения и силы тяжести.

Answer 1

Ответ:

A=FS

Объяснение:

A - работа

F - сила

S - расстояние

А = 40 * 25 = 1000Дж

Answer 2

#### Calculation of the Work Done by Friction and Gravity To determine the work done by the force of friction and the force of gravity on the car driven by Leopold the cat, we need to consider the given information. The car traveled a distance of 25 meters on a horizontal road segment. The force of friction acting on the car is equal to 40 N. #### Work Done by the Force of Friction The work done by the force of friction can be calculated using the formula: **Work = Force x Distance** In this case, the force of friction is 40 N, and the distance traveled by the car is 25 meters. Plugging these values into the formula, we can calculate the work done by the force of friction: **Work = 40 N x 25 m = 1000 J** Therefore, the work done by the force of friction is 1000 Joules (J). #### Work Done by the Force of Gravity The work done by the force of gravity can be calculated using the formula: **Work = Force x Distance x cos(θ)** In this case, the force of gravity is the weight of the car, which can be calculated using the formula: **Weight = Mass x Gravity** Unfortunately, the mass of the car and the value of gravity are not provided in the given information. Therefore, we cannot calculate the exact work done by the force of gravity without this information. Please provide the mass of the car and the value of gravity so that we can calculate the work done by the force of gravity accurately.