Question

Трехкилограммовая граната катится по земле со скоростью 3м/с. При взрыве происходит осечка и граната раскалывается на 2 равные части. Первый осколок летит в ту же сторону, что и брошенная граната, со скоростью 30 м/с. С какой скоростью и в каком направлении полетит второй осколок?

Answer 1

граната полетит в противоположную сторону со скоростью 60км/ч

 

Answer 2

Ну тут приминяется закон сохранения импульса, у нас до разрыва граната имела импульс равный: m*v1 где v1-это скорость гранаты до разрыва а  m-ее масса.

Так как в законе сохранения импульса складываются вектора а если один вектор сонаправлен с начальным, то второй должен быть направлен в другую сторону, так как никакой другой вектор не даст нужно первоначального направления.

Тогда запишем закон сохранения импульса:u=

m*v1=m/2*v2-m/2*u, найдем u:

u=24м/с

 

Answer 3

Problem Analysis

We are given that a 3-kilogram grenade is rolling on the ground with a speed of 3 m/s. When it explodes, it splits into two equal parts. The first fragment flies in the same direction as the thrown grenade with a speed of 30 m/s. We need to determine the speed and direction of the second fragment.

Solution

To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the explosion is equal to the total momentum after the explosion.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

Where: - p is the momentum, - m is the mass of the object, and - v is the velocity of the object.

Let's denote the mass of each fragment after the explosion as m1 and m2, and their velocities as v1 and v2, respectively.

Before the explosion, the momentum of the grenade is given by:

p_grenade = m_grenade * v_grenade

After the explosion, the total momentum of the two fragments is given by:

p_total = p1 + p2

Since the grenade is initially at rest, its momentum is zero. Therefore, we can write:

p_total = p1 + p2 = 0

Since the first fragment flies in the same direction as the thrown grenade, its velocity is positive. Let's substitute the values into the equation:

m1 * v1 + m2 * v2 = 0

Since the grenade splits into two equal parts, we have:

m1 = m2 = m_grenade / 2

Substituting this into the equation, we get:

(m_grenade / 2) * v1 + (m_grenade / 2) * v2 = 0

Simplifying the equation, we have:

v1 + v2 = 0

Since the first fragment has a velocity of 30 m/s, we can substitute this value into the equation:

30 + v2 = 0

Solving for v2, we find:

v2 = -30 m/s

Therefore, the second fragment will fly in the opposite direction of the thrown grenade with a speed of 30 m/s.

Answer

The second fragment will fly in the opposite direction of the thrown grenade with a speed of 30 m/s.