Question

На сколько изменилась кинетическая энергия тела массой 20 кг при увеличении его скорости с 5 до 10 м/с? С 10 до 15 м/с? На какую высоту поднимется тело, массой 134564631 кг, брошенное вертикально вверх со скоростью 20 м/с?

Answer 1

Відповідь:

Сначала кинетическая энергия  увеличится в 4 раза, потом в 2,25 раза.

На высоту 20 метров.

Пояснення:

На фото

Answer 2

#### Calculation of Change in Kinetic Energy To calculate the change in kinetic energy of an object, we can use the formula: **Change in Kinetic Energy = 1/2 * mass * (final velocity^2 - initial velocity^2)** Let's calculate the change in kinetic energy for a body with a mass of 20 kg, as its velocity increases from 5 m/s to 10 m/s and then from 10 m/s to 15 m/s. 1. Change in kinetic energy from 5 m/s to 10 m/s: - Initial velocity (v1) = 5 m/s - Final velocity (v2) = 10 m/s - Mass (m) = 20 kg Plugging these values into the formula, we get: **Change in Kinetic Energy = 1/2 * 20 kg * ((10 m/s)^2 - (5 m/s)^2)** Simplifying the equation: **Change in Kinetic Energy = 1/2 * 20 kg * (100 m^2/s^2 - 25 m^2/s^2)** **Change in Kinetic Energy = 1/2 * 20 kg * 75 m^2/s^2** **Change in Kinetic Energy = 750 J** Therefore, the change in kinetic energy when the velocity increases from 5 m/s to 10 m/s is 750 Joules. 2. Change in kinetic energy from 10 m/s to 15 m/s: - Initial velocity (v1) = 10 m/s - Final velocity (v2) = 15 m/s - Mass (m) = 20 kg Plugging these values into the formula, we get: **Change in Kinetic Energy = 1/2 * 20 kg * ((15 m/s)^2 - (10 m/s)^2)** Simplifying the equation: **Change in Kinetic Energy = 1/2 * 20 kg * (225 m^2/s^2 - 100 m^2/s^2)** **Change in Kinetic Energy = 1/2 * 20 kg * 125 m^2/s^2** **Change in Kinetic Energy = 1250 J** Therefore, the change in kinetic energy when the velocity increases from 10 m/s to 15 m/s is 1250 Joules. #### Calculation of Height Reached by an Object Thrown Vertically Upwards To calculate the height reached by an object thrown vertically upwards, we can use the formula: **Height = (initial velocity^2) / (2 * acceleration due to gravity)** In this case, the object has a mass of 134,564,631 kg and is thrown vertically upwards with an initial velocity of 20 m/s. - Mass (m) = 134,564,631 kg - Initial velocity (v0) = 20 m/s - Acceleration due to gravity (g) = 9.8 m/s^2 (approximate value on Earth) Plugging these values into the formula, we get: **Height = (20 m/s)^2 / (2 * 9.8 m/s^2)** Simplifying the equation: **Height = 400 m^2/s^2 / 19.6 m/s^2** **Height ≈ 20.41 meters** Therefore, the object will reach a height of approximately 20.41 meters when thrown vertically upwards with an initial velocity of 20 m/s. Please note that the calculations above assume ideal conditions and do not take into account factors such as air resistance.