Question

Зависимость координаты движущего тела от времени имеет вид: X=10+3t+t в квадрате(м). Найдите проекцию скорости тела через промежуток времени t=4c Помогите,пожалуйста.

Answer 1

Уравнение скорости V(t)=x'(t)=3+2*t   V(4)=3+2*4=11 м/с

Answer 2

#### Finding the Projection of Velocity To find the projection of velocity for the moving object, we need to differentiate the equation for position with respect to time. The equation for the position of the moving object is given as: **X = 10 + 3t + t^2** (in meters) To find the velocity, we differentiate the position equation with respect to time (t): **V = dX/dt** Differentiating the equation, we get: **V = d(10 + 3t + t^2)/dt** Simplifying the equation, we get: **V = 3 + 2t** Now, we can substitute the given value of t = 4c into the equation to find the projection of velocity at that time: **V = 3 + 2(4)** **V = 3 + 8** **V = 11 m/s** Therefore, the projection of velocity for the moving object at t = 4c is **11 m/s**. Please let me know if you need any further assistance!