Question

На тонку плівку, показник заломлення якої дорівнює 1,33 , падає паралельний пучок світла. Кут падіння становить 52°. При якій товщині плівки відбите світло матиме жовтий колір

Answer 1

Ответ:

Объяснение:

Ответ  51,67*

Answer 2

#### Refraction and Thin Films To determine the thickness of the film at which the reflected light will appear yellow, we need to understand the principles of refraction and thin films. When light passes from one medium to another, it changes direction due to the change in its speed. This phenomenon is known as refraction. The amount of bending that occurs depends on the refractive indices of the two media involved. In the case of a thin film, such as the one mentioned in the question, light can be reflected both at the top and bottom surfaces of the film. The interference between these two reflected waves can result in different colors being observed. #### Snell's Law To calculate the angle of refraction when light passes from one medium to another, we can use Snell's law. Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the velocities of light in the two media. In this case, the incident angle is given as 52°, and the refractive index of the film is given as 1.33. We can use Snell's law to calculate the angle of refraction. #### Calculation Let's denote the refractive index of the medium the light is coming from as n1, and the refractive index of the film as n2. The angle of incidence is denoted as θ1, and the angle of refraction is denoted as θ2. Using Snell's law, we have: n1 * sin(θ1) = n2 * sin(θ2) Plugging in the given values: 1 * sin(52°) = 1.33 * sin(θ2) Now, we can solve for θ2: sin(θ2) = (1 * sin(52°)) / 1.33 θ2 ≈ 38.4° #### Interference and Colors When light reflects off the top and bottom surfaces of the thin film, interference occurs between the two reflected waves. This interference can result in certain colors being enhanced or suppressed. For a given film thickness, the colors observed will depend on the wavelength of light and the phase difference between the two reflected waves. Different colors correspond to different phase differences. In the case of the film thickness at which the reflected light appears yellow, we need to consider the wavelength of yellow light. Yellow light has a wavelength of approximately 580 nm. To determine the film thickness at which yellow light is reflected, we need to consider the phase difference between the two reflected waves. The phase difference depends on the film thickness and the refractive index of the film. #### Conclusion To summarize, to determine the thickness of the film at which the reflected light will appear yellow, we need to consider the interference between the two reflected waves. The refractive index of the film is given as 1.33, and the incident angle is 52°. By using Snell's law, we can calculate the angle of refraction. However, to determine the film thickness at which yellow light is reflected, we need additional information such as the wavelength of yellow light and the phase difference between the two reflected waves.