Question

цепь состоит из двух последовательных соединённых резисторов сопротивлениями 4 Ом и 12 Ом​. Сила тока в первом Резисторе равна 1,2 А. каково напряжение на каждом Резисторе и общее напряжение. Можно пожалуйста полное решение

Answer 1

Ответ:

Ответ на фото

Объяснение:

Answer 2

I can help you with your question.

The circuit consists of two resistors connected in series with resistances of 4 Ω and 12 Ω. The current in the first resistor is 1.2 A. You want to know the voltage across each resistor and the total voltage. You also want a complete solution.

To solve this problem, we can use the Ohm's law and the Kirchhoff's voltage law.

Ohm's law states that the voltage across a resistor is equal to the product of the current and the resistance: $$U=IR$$

Kirchhoff's voltage law states that the sum of the voltages around any closed loop in a circuit is zero: $$\sum U=0$$

Since the resistors are connected in series, the current is the same for both of them: $$I=I_1=I_2=1.2 A$$

Using Ohm's law, we can find the voltage across each resistor:

$$U_1=I_1R_1=1.2\times 4=4.8 V$$

$$U_2=I_2R_2=1.2\times 12=14.4 V$$

Using Kirchhoff's voltage law, we can find the total voltage:

$$U+U_1+U_2=0$$

$$U=-U_1-U_2=-4.8-14.4=-19.2 V$$

The negative sign means that the total voltage is opposite to the direction of the current.

Therefore, the answer is:

- The voltage across the first resistor is 4.8 V. - The voltage across the second resistor is 14.4 V. - The total voltage is -19.2 V.

I hope this helps you understand the problem better.