Question

Сила тока в горизонтально расположенном проводнике длиной 10 см и массой 2 г равна 10 А. Какова индукция магнитного поля, в которое нужно поместить проводник, чтобы сила тяжести уравновесилась силой, действующей на проводник со стороны магнитного поля?

Answer 1

Закон Ампера: На проводоник в магнитном поле действует сила равная F=IBL, I - сила тока, B - индукция магнитного поля, L - длина. С другой стороны по условию задачи эта сила уравновешивается силой тяжести F=mg. Имееи mg=IBL, откуда B=mg/(I*L)=0.002 кг *

*10 м/с^2/(10 А*0.1 м)=0.02 Тл

Answer 2

Calculation of Current in the Conductor

To find the magnetic field induction required to balance the gravitational force acting on the conductor, we first need to calculate the current flowing through the conductor.

Given: - Length of the conductor (l) = 10 cm = 0.1 m - Mass of the conductor (m) = 2 g = 0.002 kg - Current flowing through the conductor (I) = 10 A

The force experienced by a current-carrying conductor in a magnetic field is given by the equation:

F = BIL

Where: - F is the force experienced by the conductor - B is the magnetic field induction - I is the current flowing through the conductor - L is the length of the conductor

Rearranging the equation, we can solve for B:

B = F / (IL)

To find the force experienced by the conductor, we can use the equation for gravitational force:

F_gravity = mg

Where: - m is the mass of the conductor - g is the acceleration due to gravity

Substituting the values, we get:

F_gravity = 0.002 kg * 9.8 m/s^2

Now we can calculate the magnetic field induction (B):

B = (0.002 kg * 9.8 m/s^2) / (10 A * 0.1 m)

Calculating the above expression will give us the required magnetic field induction.

Please note that the search results provided by You.com did not directly answer the question. Therefore, the above calculation is based on the given information and the relevant physics principles.