Question

Физика,очень срочно Из пушки массой 500 кг установленной на горизонтальной поверхности производят под углом в 30 градусов к горизонту, выстрел снаряда массой 20 кг со скоростью 200м/с относительно земли. Найдите скорость пушки приобретенную его в момент выстрела.

Answer 1

20 кг отн. 500=1/25 200/25=8м/с ?

Answer 2

Calculation of the Cannon's Velocity

To find the velocity of the cannon at the moment of firing, we can use the principle of conservation of momentum. The total momentum before the shot is equal to the total momentum after the shot.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the cannon as m_cannon (500 kg) and the mass of the projectile as m_projectile (20 kg). The initial velocity of the projectile relative to the ground is v_projectile (200 m/s).

Before the shot, the cannon is at rest, so its initial velocity is 0 m/s. After the shot, the cannon and the projectile move together with a common velocity, which we'll denote as v_common.

Using the conservation of momentum, we can write the equation:

(m_cannon + m_projectile) * v_common = m_cannon * v_cannon + m_projectile * v_projectile

Since the cannon is initially at rest, v_cannon is 0 m/s. Plugging in the known values, we can solve for v_common:

(500 kg + 20 kg) * v_common = 500 kg * 0 m/s + 20 kg * 200 m/s

Simplifying the equation:

520 kg * v_common = 4000 kg m/s

Dividing both sides by 520 kg:

v_common = 4000 kg m/s / 520 kg

Calculating the value:

v_common ≈ 7.69 m/s

Therefore, the velocity of the cannon at the moment of firing is approximately 7.69 m/s.

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