Question

В цилиндре под поршнем изобарически охлаждают газ объемом V1= 10 л от температуры Т1= 323 К до температуры Т2= 273 К. Каков объем газа при температуры Т2 ?

Answer 1

V2=(T2V1)/T1
V2=(273×10)/373=7,3л

Answer 2

Calculation of Gas Volume at Temperature T2

To calculate the volume of gas at temperature T2, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (assumed to be constant in this case, as the process is isobaric) - V is the volume of the gas - n is the number of moles of gas - R is the ideal gas constant - T is the temperature of the gas

In this case, the process is isobaric, which means the pressure remains constant. Therefore, we can rewrite the equation as:

V1/T1 = V2/T2

Where: - V1 is the initial volume of the gas - T1 is the initial temperature of the gas - V2 is the final volume of the gas (which we want to find) - T2 is the final temperature of the gas

Given: - V1 = 10 L - T1 = 323 K - T2 = 273 K

We can rearrange the equation to solve for V2:

V2 = (V1 * T2) / T1

Substituting the given values:

V2 = (10 * 273) / 323

Calculating the value:

V2 ≈ 8.49 L

Therefore, the volume of the gas at temperature T2 is approximately 8.49 liters.