Question

Пуля вылетает из винтовки в горизонтальном направлении со скоростью 850 м/с. какую скорость приобретает винтовка при отдаче,если ее масса больше массы пули в 500 раз?

Answer 1

По закону сохранения импульса: m1*v1=m2*v2. (m1-масса винтовки, m2-масса пули, v1-скорость винтовки (отдачи) , v2-скорость пули) , выразим v1.
v1=m2*v2 / m1, так как, по условиям m1=500 m2, подставим, и сократим на m2.
v1=m2*v2 / 500m2
v1=v2 / 500.
v1=850/500=2м/c.
v1=2м/c.
Можно проще, если масса в 500 раз больше, то скорость будет а 500 раз меньше.
v1=v2 / 500=850 / 500=2м/c.

Answer 2

Calculation of Rifle Velocity

To calculate the velocity acquired by the rifle during recoil, we can use the principle of conservation of momentum. According to this principle, the total momentum before the shot is equal to the total momentum after the shot.

Let's denote the mass of the bullet as m1 and the mass of the rifle as m2. The initial velocity of the bullet is given as V1 = 850 m/s in the horizontal direction. We need to find the velocity acquired by the rifle, denoted as V2.

Using the conservation of momentum equation, we have:

m1 * V1 = m2 * V2

Given that the mass of the rifle is 500 times greater than the mass of the bullet, we can express m2 in terms of m1:

m2 = 500 * m1

Substituting this into the conservation of momentum equation, we get:

m1 * V1 = (500 * m1) * V2

Simplifying the equation, we find:

V2 = (m1 * V1) / (500 * m1)

Simplifying further, we get:

V2 = V1 / 500

Now we can substitute the given value of V1 = 850 m/s into the equation to find the velocity acquired by the rifle:

V2 = 850 m/s / 500 = 1.7 m/s

Therefore, the rifle acquires a velocity of 1.7 m/s in the opposite direction during recoil.