Question

Какое количество теплоты потребуется для нагревания на 18 градусов воздуха в комнате, размеры которой 4м на 5м на 2.5 м? Сколько воды можно на греть этой же тепловой на такое же число градусов?

Answer 1

1.Q=cmt=cVpt=1*50*1, 293*18=1163, 7Дж
2.V=Q/cpt=1163,7/4,19*1028*18=0, 015м^3

Answer 2

Calculating Heat Required to Heat the Room:

To calculate the amount of heat required to raise the temperature of the air in the room by 18 degrees, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat required, - m is the mass of the air, - c is the specific heat capacity of air, and - ΔT is the change in temperature.

The mass of the air can be calculated using the formula:

m = ρV

Where: - ρ is the density of air, and - V is the volume of the room.

The specific heat capacity of air is approximately 1.005 kJ/kg°C.

Given: - The dimensions of the room are 4m x 5m x 2.5m.

Let's calculate the amount of heat required to heat the air in the room by 18 degrees.

Calculation:

The volume of the room is: V = 4m x 5m x 2.5m = 50m³

The mass of the air can be calculated using the density of air, which is approximately 1.225 kg/m³: m = 1.225 kg/m³ x 50m³ = 61.25 kg

Now, we can calculate the amount of heat required using the specific heat capacity of air: Q = 61.25 kg x 1.005 kJ/kg°C x 18°C = 1100.25 kJ

So, the amount of heat required to raise the temperature of the air in the room by 18 degrees is approximately 1100.25 kJ.

Heating Water by the Same Amount:

To calculate the amount of water that can be heated by the same amount of heat to the same temperature change, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat required, - m is the mass of the water, - c is the specific heat capacity of water, and - ΔT is the change in temperature.

The specific heat capacity of water is approximately 4.186 kJ/kg°C.

Given: - The temperature change is 18 degrees.

Let's calculate the amount of water that can be heated by the same amount of heat to the same temperature change.

Calculation:

We already know the amount of heat required (Q) is 1100.25 kJ, and the temperature change (ΔT) is 18°C.

Using the formula Q = mcΔT, we can rearrange it to solve for the mass of water (m): m = Q / cΔT

Substituting the values: m = 1100.25 kJ / (4.186 kJ/kg°C x 18°C) ≈ 15.73 kg

So, the amount of water that can be heated by the same amount of heat to the same temperature change is approximately 15.73 kg.