Question

M=30г2 M=18•10`-3 кг/моль Т=100К Р=10кПа V-?

Answer 1

А=Pv=m/M×RT
Внизу стоит решиение на фото

Answer 2

To calculate the volume (V), we can use the ideal gas law equation, which is given by:

PV = nRT

where: P = pressure in Pascal (Pa) V = volume in cubic meters (m³) n = number of moles of the gas (in this case, n = M / molar mass) R = ideal gas constant (approximately 8.314 J/(mol K)) T = temperature in Kelvin (K)

Let's plug in the values:

M = 30 g/mol (molar mass of the gas) M = 18 * 10^(-3) kg/mol (converted molar mass to kg/mol) T = 100 K P = 10 kPa (converted to Pa, where 1 kPa = 1000 Pa)

First, let's calculate the number of moles (n):

n = M / molar mass n = (18 * 10^(-3) kg/mol) / (30 g/mol) (converting the molar mass to kg/mol) n = 0.6 / 0.03 n = 20 moles

Now, let's calculate the volume (V):

V = nRT / P V = (20 moles) * (8.314 J/(mol K)) * (100 K) / (10,000 Pa) (converted kPa to Pa) V = (20 moles) * (8.314 J/(mol K)) * (100 K) / (10,000 N/m²) V = (20 moles) * (8.314 J/(mol K)) * (100 K) / (10,000 J/m³) V = 20 * 8.314 * 100 / 10,000 m³ V = 166.28 / 10,000 m³ V = 0.016628 m³

So, the volume of the gas at the given conditions is approximately 0.0166 cubic meters (m³).