Question

V=20дм3 T=300k P=3600ПаНайти N

Answer 1

Воспользуемся формулой p=nkT(1). n=$\frac{N}{V}$(2) подставим формулу 2 в 1 и получим, что p=$\frac{N}{V}$×kT, откуда N=$\frac{PV}{KT}$.  Подставим числа и получим, что N=$\frac{3600*20}{1.38*10^{-23} *300} =173*10^{23}$

Answer 2

To find the number of moles (N) of a gas, we can use the ideal gas law equation:

PV = nRT

where: P = pressure of the gas (in Pascal, Pa) V = volume of the gas (in cubic meters, m^3) n = number of moles of gas R = ideal gas constant (approximately 8.314 J/(mol·K)) T = temperature of the gas (in Kelvin, K)

Before we proceed, we need to convert the given values to the appropriate units:

V = 20 dm^3 = 20 × 10^(-3) m^3 (1 dm^3 = 0.001 m^3) T = 300 K P = 3600 Pa

Now, we can solve for N:

N = (PV) / (RT)

N = (3600 Pa × 20 × 10^(-3) m^3) / (8.314 J/(mol·K) × 300 K)

N ≈ 0.2882 moles

So, the number of moles (N) of the gas is approximately 0.2882 moles.