Question

M1 = 400 m2 = 600 v1 = 2м/с V2 = 1 м/с Удар не упругий V1,2 - ?

Answer 1

пусть скорость после столкновения v1, а до столкновения v

v1(m1+m2)=v*(m1-m2)

v1=(m1-m2)v/(m1+m2)=(0,6-0,2)*2/(0,6+0,2)=0,8/0.8=1

ответ 1 м/c

Это не точно!!!я в 6классе просто шарю

Answer 2

To solve for the final velocities of the two masses (m1 and m2) after the inelastic collision, we can use the conservation of momentum and the concept of an inelastic collision.

In an inelastic collision, the two objects stick together after the collision. The total momentum before the collision is equal to the total momentum after the collision.

The formula for momentum is:

Momentum = mass × velocity

Conservation of momentum equation:

Total initial momentum = Total final momentum

(m1 × v1) + (m2 × v2) = (m1 + m2) × V

where V is the final common velocity of both masses after sticking together.

Given: m1 = 400 kg (mass of the first object) v1 = 2 m/s (velocity of the first object) m2 = 600 kg (mass of the second object) v2 = 1 m/s (velocity of the second object)

Let's plug in the values and solve for V:

(400 kg × 2 m/s) + (600 kg × 1 m/s) = (400 kg + 600 kg) × V

(800 kg m/s) + (600 kg m/s) = (1000 kg) × V

1400 kg m/s = 1000 kg × V

Now, let's solve for V:

V = 1400 kg m/s / 1000 kg

V = 1.4 m/s

So, the final common velocity (V1,2) of both masses after the inelastic collision is 1.4 m/s.