Question

I=1 АQ1 = 30 Джt1= 3 сR1=R2t2=2сI =2АQ2 = ? "​

Answer 1

Вы не уточнили саму задачу, поэтому (я так думаю) напряжение в обоих случаях одинаковое по той или иной причине.

Решение:

Q1=UIt

U=Q/It=30/(1*3)=10В

Q2=UIt=10*2*2=40Дж

Answer 2

To find the value of Q2, we can use the equation for electrical energy:

Energy (Q) = Current (I) × Time (t) × Resistance (R)

We have the following information:

I1 = 1 A (current in the first situation) Q1 = 30 J (electrical energy in the first situation) t1 = 3 s (time in the first situation) R1 = R2 (resistance in the first situation is equal to resistance in the second situation) t2 = 2 s (time in the second situation) I2 = 2 A (current in the second situation, which we need to find) Q2 = ? (electrical energy in the second situation, which we need to find)

From the given data, we know that:

Q1 = I1 × t1 × R1

Now, we can rearrange the equation to find the resistance:

R1 = Q1 / (I1 × t1)

Since R1 = R2, we can use the same resistance value for the second situation:

R2 = Q1 / (I1 × t1)

Now, let's find Q2 using the formula:

Q2 = I2 × t2 × R2

Substitute the value of R2:

Q2 = I2 × t2 × (Q1 / (I1 × t1))

Now, plug in the given values:

Q2 = 2 A × 2 s × (30 J / (1 A × 3 s))

Q2 = 2 A × 2 s × (10 J)

Q2 = 40 J

Therefore, in the second situation, the electrical energy Q2 is 40 Joules.