Question

Тело массой 7000 кг падает с высоты 2 метра с какой скоростью падает тело?

Answer 1

Ответ:

Объяснение:

$mgh =\dfrac{mv^2}{2} \to v = \sqrt{2gh} = \sqrt{2*10*2} = 6.32\dfrac{m}{s}$

Answer 2

To calculate the speed (velocity) at which the object falls, we can use the principles of kinematics. The formula to calculate the final velocity (v) of an object in free fall is:

v^2 = u^2 + 2 * g * h

where: v = final velocity (m/s) u = initial velocity (in this case, it's 0 m/s as the object is dropped) g = acceleration due to gravity (approximately 9.81 m/s^2 on the surface of the Earth) h = height (2 meters)

Let's plug in the values and solve for v:

v^2 = 0 + 2 * 9.81 * 2 v^2 = 0 + 39.24 v = √39.24 v ≈ 6.26 m/s

So, the body will be falling with a velocity of approximately 6.26 meters per second.