Question

Найдите показатель преломления среды, если луч, преломленный на границе этой среды с воздухом перпендикулярен отраженному, а синус угла падения равен 0,8.

Answer 1

Ответ:

n=1.34

Объяснение:

sinα=0.8    n=?

===

α=arcsin0.8=53.5°

γ=180-(α+90)=36.5°

n=sinα/sinγ=0.8/0.595≈1.34

==========================

Answer 2

Calculation of the Refractive Index

To find the refractive index of a medium, given that the refracted ray at the boundary of the medium with air is perpendicular to the reflected ray and the sine of the angle of incidence is 0.8, we can use Snell's law.

Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the speeds of light in the two media. Mathematically, it can be expressed as:

n1 * sin(θ1) = n2 * sin(θ2)

Where: - n1 is the refractive index of the incident medium (in this case, air) - θ1 is the angle of incidence - n2 is the refractive index of the refracted medium (the medium we want to find the refractive index of) - θ2 is the angle of refraction

In this case, since the refracted ray is perpendicular to the reflected ray, the angle of refraction is 90 degrees. Therefore, sin(θ2) = 1.

Given that sin(θ1) = 0.8, we can rearrange the equation to solve for the refractive index of the medium:

n2 = (n1 * sin(θ1)) / sin(θ2)

Since n1 is the refractive index of air, which is approximately 1, we can substitute the values into the equation:

n2 = (1 * 0.8) / 1 = 0.8

Therefore, the refractive index of the medium is approximately 0.8.

Please note that the specific medium is not mentioned in the question, so we cannot provide a more specific answer.