Question

M = 15kг t1 = 150°с t2 = 750°С c = 400 дж:кг°с Q?​

Answer 1

Дано:

m = 15 кг

t1 = 150 °c

t2 = 750 °c

c = 400 Дж/(кг°с)

Найти:

Q-?

Решение:

Q=c*m*(c2-c1)=400*15*(750-150)=3,6*10^6 Дж

Ответ:

Q=3,6*10^6 Дж

Answer 2

To find the heat transfer (Q) required to raise the temperature of a mass (M) from one temperature (t1) to another temperature (t2) using the specific heat capacity (c), you can use the following formula:

Q = M * c * ΔT

Where: Q = heat transfer (in joules, J) M = mass (in kilograms, kg) c = specific heat capacity (in J/(kg·°C)) ΔT = change in temperature (in °C), which is equal to t2 - t1

Now, plug in the values from your question:

M = 15 kg t1 = 150°C t2 = 750°C c = 400 J/(kg·°C)

First, calculate ΔT:

ΔT = t2 - t1 ΔT = 750°C - 150°C ΔT = 600°C

Now, plug these values into the formula:

Q = 15 kg * 400 J/(kg·°C) * 600°C Q = 3,600,000 J

So, the heat transfer required to raise a 15 kg mass from 150°C to 750°C using a specific heat capacity of 400 J/(kg·°C) is 3,600,000 joules (J).