Question

ПОЖАЛУЙСТА КАК МОЖНО БЫСТРЕЕ! Кролик Роджер уронил свою цилиндрическую шляпу массой 800 г, высотой 10 см и площадью дна 2 дм2 в цилиндрическую бочку высотой 100 см и площадью дна 20 дм2, заполненную водой. Шляпа не касается стенок бочки, не намокает, не протекает, донышко шляпы горизонтально, вода из бочки не выливается. Плотность воды 1 г/см3. 1) Как изменится уровень воды в бочке? Повысится или понизится 2) Будет ли плавать шляпа или утонет? Утонет или будет плавать 3)На сколько миллиметров изменился уровень воды в бочке после того, как в неё попала шляпа? ​

Answer 1

Ответ:

900/10=90

90*2=180

180-100=80

Answer 2

Ответ:

1. Уровень не изменится. 2. Будет плавать. 3. Ни насколько.

Объяснение:

Шляпа не намокает не тяжелеет и не

тонет.

Если ответ не точный извините пожалуйста.

Answer 3

The Effect of Dropping a Hat into a Barrel of Water

When the rabbit Roger dropped his cylindrical hat into a barrel filled with water, several questions arise regarding the water level in the barrel, the buoyancy of the hat, and the change in water level after the hat is dropped.

To answer these questions, let's analyze the situation step by step.

1. How will the water level in the barrel change? - The water level in the barrel will rise when the hat is dropped into it. This is because the hat displaces a volume of water equal to its own volume, causing the water level to increase. - The amount by which the water level rises can be calculated using Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. - In this case, the weight of the water displaced by the hat is equal to the weight of the hat itself, which is 800 grams. - Since the density of water is 1 gram per cubic centimeter (1 g/cm³), the volume of water displaced by the hat is 800 cm³. - Therefore, the water level in the barrel will rise by 800 cm³ or 0.8 liters.

2. Will the hat float or sink? - The hat will float in the barrel of water. This is because the density of the hat is less than the density of water. - The density of an object can be calculated by dividing its mass by its volume. - In this case, the mass of the hat is 800 grams and its volume can be calculated using the formula for the volume of a cylinder: V = πr²h, where r is the radius and h is the height. - The radius of the hat can be calculated by dividing its diameter (which is not given) by 2. Since the hat is cylindrical, we can assume that its diameter is equal to its height, which is 10 cm. - Therefore, the radius of the hat is 5 cm. - Using the formula for the volume of a cylinder, we can calculate the volume of the hat as follows: V = π(5 cm)²(10 cm) = 250π cm³. - The density of the hat is then calculated as follows: density = mass/volume = 800 g / 250π cm³ ≈ 1.02 g/cm³. - Since the density of the hat is greater than the density of water (1 g/cm³), the hat will float in the barrel.

3. How much will the water level change after the hat is dropped? - The water level in the barrel will rise by 0.8 liters when the hat is dropped into it, as mentioned earlier. - To convert this volume to millimeters, we need to know the dimensions of the barrel's base. - The area of the barrel's base is given as 20 dm², which is equal to 2000 cm². - Dividing the volume change (0.8 liters or 800 cm³) by the base area (2000 cm²) gives us the change in water level per unit area. - Therefore, the water level in the barrel will rise by 0.4 cm or 4 mm for every square centimeter of the base area.

In summary, when the cylindrical hat with a mass of 800 grams, a height of 10 cm, and a base area of 2 dm² is dropped into a cylindrical barrel with a height of 100 cm and a base area of 20 dm² filled with water, the water level in the barrel will rise by 0.8 liters or 800 cm³. The hat will float in the water, and the water level in the barrel will rise by 4 mm for every square centimeter of the base area.

Please let me know if you need any further clarification or have any other questions!