Question

тело брошено с некоторой высоты горизонтально со скоростью V0=30 м/с.Если в момент падения на землю вектор его скорости направлен 60° к горизонту, то чему равна скорость в этот момент по модулю?

Answer 1

Ответ:

60 м/с

Объяснение:

vox=30 м/с    α=60°    v=?

===

v=vox/cosα=30/0.5=60 м/с

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Answer 2

Calculation of the Velocity at the Moment of Impact

To calculate the velocity at the moment of impact, we can use the given information. The body is thrown horizontally with an initial velocity of V0 = 30 m/s. At the moment of impact, the velocity vector is directed at an angle of 60° to the horizon.

To find the velocity at the moment of impact, we can use the horizontal and vertical components of the initial velocity.

The horizontal component of the velocity remains constant throughout the motion because there are no horizontal forces acting on the body. Therefore, the horizontal component of the velocity at the moment of impact is the same as the initial horizontal velocity, which is V0 = 30 m/s.

The vertical component of the velocity changes due to the effect of gravity. The body falls vertically under the influence of gravity, so we can use the equations of motion to find the vertical component of the velocity at the moment of impact.

Let's denote the vertical component of the velocity at the moment of impact as V_y.

Using the equation of motion for vertical motion, we have:

V_y = V0_y + g * t

Since the body is thrown horizontally, the initial vertical velocity (V0_y) is zero.

Therefore, the equation simplifies to:

V_y = g * t

To find the time of flight (t), we can use the equation:

h = (1/2) * g * t^2

where h is the height from which the body is thrown.

From the given information, we don't have the value of h. Therefore, we cannot calculate the exact value of the velocity at the moment of impact without knowing the height from which the body is thrown.

Please provide the height from which the body is thrown so that we can calculate the velocity at the moment of impact.