Question

Провідник увімкнено в коло з сталою напругою 120 В. Сила струму у провіднику 1.5 А Послідовно з провідником ввімкнули додатковий опір. Сила струму у колі стала 1.2 А. Знайти додатковий опір. Допоможіть будь ласка!!!

Answer 1

Ответ: 20 Ом

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U = 120 B

А₁ = 1.5

А₂ = 1.2

R = ?

Объяснение:

R1 = U/I1 = 120/1.5 = 80 Oм

R1.2 = U/I1.2 = 120/1.2 = 100 Oм

R1.2 = R1 + R2

R2 = R1.2 - R1 = 100 - 80 = 20 Oм

Answer 2

Calculation of Additional Resistance in the Circuit

To find the additional resistance in the circuit, we can use Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage across it and inversely proportional to the resistance.

Given: - Voltage across the conductor (V1) = 120 V - Current through the conductor (I1) = 1.5 A - Current through the circuit (I2) = 1.2 A

We can use the formula:

V = I * R

where V is the voltage, I is the current, and R is the resistance.

Let's calculate the resistance of the conductor (R1) using the given values:

R1 = V1 / I1

Substituting the values, we get:

R1 = 120 V / 1.5 A = 80 Ω [[1]]

Now, let's calculate the resistance of the circuit (R_total) using the current through the circuit (I2) and the voltage across the conductor (V1):

R_total = V1 / I2

Substituting the values, we get:

R_total = 120 V / 1.2 A = 100 Ω [[1]]

To find the additional resistance (R_additional), we subtract the resistance of the conductor (R1) from the total resistance (R_total):

R_additional = R_total - R1

Substituting the values, we get:

R_additional = 100 Ω - 80 Ω = 20 Ω

Therefore, the additional resistance in the circuit is 20 Ω.

I hope this helps! Let me know if you have any further questions.